m^2-4m=2 find the factors by using quadratic equation formula
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Answer:
m=2+√6 and 2-√6
Explanation:
m^2-4m-2=0
comparing by equation ax^2+bx+c=0
a=1 ,b=-4, c=-2
m=(-b+√b^2-4ac)/2a and( -b-√b^2-4ac)/2a
m={4+√(-4)^2-4(1)(-2)}/2(1) and{4-√(-4)^2-4(1)(-2)}/2(1)
m=2+√6 or 2-√6
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