m^2(m+2n)(m-4n) , please solve
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Answered by
2
Answer:
Hope it helps you.............
Step-by-step explanation:
Given -
m²(m + 2n)(m - 4n)
First we solve \textbf{(m + 2n)(m - 4n)}(m + 2n)(m - 4n)
Using identity -
(x + a)(x + b) = x² + (a + b)x + ab
Here, x = m, a = 2n and b = - 4n
•°•
(m + 2n)(m - 4n) =
= m² + [(2n) + (- 4n)] (m) + (2n)(- 4n)
= m² + (- 2n)(m) + (- 8n²)
= m² - 2mn - 8n²
Now, Back to the question
So, we can write
m²(m² - 2mn - 8n²)
= m⁴ - 2m³n - 8m²n²
Sorry but copied from brainly website .
SO SORRY
Answered by
1
Step-by-step explanation:
m^2(m^2-4mn+2mn-8n^2)
m^2(m^2-2mn-8n^2)
m^4-2m^3n-8m^2n^2
m^4+2m^3n-4m^3n-8m^2n^2
m^3(m+2n)-4m^2n(m+2n)
(m^3-4m^2n)(m+2n).
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