Question

m
2 m/s
5 kg
As a =
and u = 3 m/s.
v = u + at = 3 m/s + (2 m/s) (5 s)
13 m/s.
Unsolved Numerical Problems for Practice
1. The motion of a body of mass 5 kg is shown in the Figure 2.15.
Find (a) its acceleration (b) the force acting on the body (c) change in
momentum of body 2 s after the start.
[CBSE 2011]
2. For how much time should a force of 400 N be exerted on a body of mass 8 kg
to increase its velocity from 150 m/s to 300 m/s ?
[CBSE 2011]
3. The force of attraction between two bodies is 20 N. Calculate the force between
them when mass of each body as well as distance between them are halved.
[CBSE 2010]
4. A cricket ball of mass 70 g moving with a velocity of 0.5 m/s is stopped by a
player in 0.5 s. What is the force applied by the player to stop the ball ?
[DAV 2005]
FIGURE 2.15
Progress Check 2
Fill in the blanks :
1. Product of mass and velocity of a body is called momentumwhich is a
rector quantity.
2. Momentum changes in the same direction as velocity of the object.
3. Sl unit of momentum is Ro mls and its CGS unit is
unit is a
gomis
4 1 ko m/s =
nomic​

Answer 1

Answer:

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