Question

(m+2)×(m²-y-n)pls give me the answer ​

Answer 1

Answer:

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Answer 2

Applying derivative

y1m−1my1−y−1m−1my1=2⟹(y1m−y−1m)=2myy1

Now, (y1m−y−1m)2=(y1m+y−1m)2−4

⟺(2myy1)2=(2x)2−4

⟺m2y2=(x2−1)y21

Applying derivative m2(2yy1)=2xy21+(x2−1)2y1y2

Cancelling 2y1(assuming ≠0)

⟺m2y=xy1+(x2−1)y2

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