Question

m^2.sinπ/2-n^2sin3π/2+2mncosecπ/2=(m+n)^2

Answer 1

Answer:

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Answer 2

Answer:

$=> m^{2}.sin\frac{\pi }{2} - n^{2} sin\frac{3\pi }{2} + 2mn cosec\frac{\pi }{2} \\=> m^{2} - n^{2} (-1) + 2 mn \\=> m^{2} + n^{2} + 2mn\\ => (m + n) ^{2}\\Hence Proved$

Step-by-step explanation: