(m+2)sin theta + (2m-1)cos theta=2m+1
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Answer:
Let t=tan
2
2
θ
(m+2)sinθ+(2m−1)cosθ=2m+1
⇒(m+2)
1+t
2
2t
+(2m−1)
1+t
2
1−t
2
=2m+1
2mt+4t+2m−2mt
2
−1+t
2
=2m+2mt
2
+1+t
2
⇒(2t−1)(mt−1)=0
Gives t=
2
1
or t=
m
1
For t=tan
2
2
θ
=
2
1
⇒tanθ=
1−t
2
2t
=
1−
4
1
1
=
3
4
For t=tan
2
2
θ
=
m
1
⇒tanθ=
1−t
2
2t
=
1−
m
2
1
2
m
1
=2m(m
2
−1)
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