Question

(m+2)sinA+(2m-1)cosA=2m+1​

Answer 1

Step-by-step explanation:

(m+2) Sin A +(2m-1) Cos A = 2m+1--------1

we know that ,

Sin A =(2 tan(A/2))/(1+tan2(A/2) and Cos A = (1-tan2(A/2))/(1+tan2(A/2)

let tan(A/2) = k and it in first equation

We get,

(m+2)(2k)/(1+k2) + (2m-1)(1-k2)/(1+k2) = 2m+1

(2m+4)k+(2m-1)-(2m-1)k2 = (2m+1)(1+k2)

(4m)k2-(2m+4)k+2=0 ---------2

By solving eq 2 we get,

k=1/m or k=0.5

tan(A/2)=1/m or tan(A/2) =0.5

A/2 = tan ⁻¹(1/m) 0r A/2 =tan ⁻¹(0.5)

A=2tan ⁻¹(1/m) or 53.130102354

tan A=tan (2tan ⁻¹(1/m) or 4/3

Answer 2

Answer:

tan theta = 2m/m^2+1 will satisfy the given equation

Step-by-step explanation:

hope it helps you Radhe Radhe ❤️