Question

m ^ { 2 } x ^ { m } -mx+mx ^ { m-1 } =0​

Answer 1

Answer:

${m}^{2} {x}^{m} - mx + m {x}^{m - 1} = 0$

take m as common

${m} {x}^{m} - x + {x}^{m - 1} = 0$

take x as common

${m} {x}^{m - 1} - 1 + m {x}^{m - 2} = 0 \\ {x}^{m - 1} + {x}^{m - 2} = \frac{1}{m} \\ \frac{1}{x} + \frac{1}{ {x}^{2} } = \frac{1}{m \times {x}^{m} }$