Math, asked by rkarthikrampandian, 3 days ago

m^3 + 1/m^3 - 23. What is the formula used to factorise thsi equation. Please factorise and tell the correct answer. With full explanation. Refer the photo for reference

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Answers

Answered by udaykharat78
1

Answer:

m²–3m=1, what is the value of m³–1/m³?

Solution:

m2−3m=1m2−3m=1

m2−3m−1=0m2−3m−1=0

Use the Quadratic Equation: m=−b±(b)2−(4⋅a⋅c)√(2⋅a)m=−b±(b)2−(4⋅a⋅c)(2⋅a)

a = 1, b = -3, and c = -1

m=−(−3)±(−3)2−(4⋅1⋅−1)√(2⋅1)m=−(−3)±(−3)2−(4⋅1⋅−1)(2⋅1)

m = 3+13√2,3+132, ==> 3.302775638

m = 3−13√2,3−132, ==> -.3027756377

You have two real answers for m.

Find value for (m3−1)m3(m3−1)m3

m = 3.302775638

(3.3027756382−1)3.3027756383(3.3027756382−1)3.3027756383

= 19−5⋅13−−√19−5⋅13 , = .9722446227

m = -.3027756377

(−.30277563773−1)−.30277563773(−.30277563773−1)−.30277563773

= 19+5⋅13−−√19+5⋅13 , = 37.02775636

Answer is: m= {37.02775636, .9722446227

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