Question

m^ + 3 √3m +6

koi to solve kar ​

Answer 1

Answer:

nhi ata

Step-by-step explanation:

I don't understand

Answer 2

Answer:

m2−3m−1=0

m2−3m=1

Third term =(21coeeficientofm)2

(21×(−3))2=(2−3)2=49

Adding P49 to both sides of equation (1), we get

m2−3m+49=1+49

∴ m2−3m+49=44+9

∴ (m−23)2=413

Taking square roots on both sides

∴ m−23=±213

∴