Question

m^3-m^2n+mn^2-n^3 factorise

Answer 1

Answer:

The answer is $(m-n)(m^2+n^2)$

Step-by-step explanation:

    $m^3-m^2n+mn^2-n^3$

$=(m^3-m^2n)+(mn^2-n^3)$, group the terms

$=m^2(m-n)+n^2(m-n)$, factor both terms

$=(m-n)(m^2+n^2)$, factor out common term