Question

m^3-n^3-m(m^2-n^2)+n(m-n)^2 simplofy

Answer 1

$m3 - n3 - m(m^{2} - n^{2}) + n(m - n^{2}) \\ m3 - n3 - m3 + mn^{2} + n(m^{2} + n^{2} - 2mn) \\ m3 - n3 - m3 + mn^{2} + m^{2}n + n3 - 2mn \\ - mn^{2} + m^{2}n \\ mn(m - n)$

Answer 2

$m^3-n^3-m(m^2-n^2)+n(m-n)^2=nm^2-mn^2$

Step-by-step explanation:

Given : Expression $m^3-n^3-m(m^2-n^2)+n(m-n)^2$

To find : Simplify the expression ?

Solution :

Solving the expression by opening the bracket first,

$=m^3-n^3-m^3+mn^2+n(m^2+n^2-2mn)$

$=m^3-n^3-m^3+mn^2+nm^2+n^3-2mn^2$

$=nm^2-mn^2$

Therefore, $m^3-n^3-m(m^2-n^2)+n(m-n)^2=nm^2-mn^2$

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