Question

m^3-n^3-m(m^2-n^2)+n(m-n) ^3​

Answer 1

Answer:

Solving the expression by opening the bracket first,

=m^3-n^3-m^3+mn^2+n(m^2+n^2-2mn)

=m^3-n^3-m^3+mn^2+nm^2+n^3-2mn^2

=nm^2-mn^2

Therefore, m^3-n^3-m(m^2-n^2)+n(m-n)^2=nm^2-mn^2

Simplify (2x+5y)²-(2x-5y) ²​

Answer 2

Step-by-step explanation:

m³-n³-m(m²-n²)+n(m-n)³

m³-n³-m³+mn²+n[m³-n³-3mn(m-n)]

-n³+mn²+nm³-nm³-3mn²(m-n)

-n³+mn²-3m²n²+3mn³