Question

(m) 38-43x+4= 0
(1) 2x2 – 3x + 5 = 0
(ii) 2x2 - 6x +3=0​

Answer 1

Answer:

$2x^{2}-3x+5=0$ roots are 5/2 and 1.

$2x^2-6x+3=0$ roots are $\frac{3+\sqrt{6}}{2}$ and $\frac{3-\sqrt{6} }{2}$

$3x^{2} -4\sqrt{3}x+4=0$ root is $\frac{2\sqrt{3} }{3}$ real and same.

Step-by-step explanation:

The roots of a quadratic equation of the form $ax^{2} +bx+c=0$ are

$\frac{-b+\sqrt{b^{2}-4ac } }{2a}$ and $\frac{-b-\sqrt{b^{2}-4ac } }{2a}$.