Question

M
(4) In the given figure MNOP is
a cyclic quadrilateral.
If P = 4x + 12, and
N
ZN = 3x + 28 then find the
value of x.
Complete the following activity.
Opposite angles of a cyclic quadrilateral are
... ZP +
= 180°
O
.. (4r + 12)+(3x +28) =
.: 7x + 40 = 180°
.: 7x = 140°
r =
fimm P in the centre of the circle BC is a diameter.​

Answer 1

Answer:

Angle p= Angle N (Vertically opposite angles)

4x+12=3x+28

x=16

Opposite angles of a cyclic quadrilateral is 180°

Angle P+Angle N= 180°

7x+40=180°

7x=140°

x= 140°/7= 20°

Step-by-step explanation:

Hope my answer will help you a lot