Question

(√m^4n^4)×(6√ m^2n^2)×(3√ m^2n^2) = (m.n)^k, then find the
value of k.
(1) 6
(2) 3
(3) 2
(4) 1
(Maharashtra, Stage-1, 2016-17)​

Answer 1

Answer:

Step-by-step explanation:

m²(m + 2n)(m - 4n)

First we solve

Using identity -

(x + a)(x + b) = x² + (a + b)x + ab

Here, x = m, a = 2n and b = - 4n

•°•

(m + 2n)(m - 4n) =

= m² + [(2n) + (- 4n)] (m) + (2n)(- 4n)

= m² + (- 2n)(m) + (- 8n²)

= m² - 2mn - 8n²

Now, Back to the question

So, we can write

m²(m² - 2mn - 8n²)

= m⁴ - 2m³n - 8m²n²

Answer 2

Answer:

the value of k is 3.