m√5 = m√2 + 1, find m
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M√5=m√2+1
M√5-m√2=1
M(√5-√2)=1
M=1/√5-√2
M√5-m√2=1
M(√5-√2)=1
M=1/√5-√2
Answered by
1
Hi ,
m√5 = m√2 + 1
m√5 - m√2 = 1
m ( √5 - √2 ) = 1
m = 1 / ( √5 - √2 )
m = ( √5 + √2 ) / ( √5 - √2 )( √5 + √2 )
m = ( √5 + √2 ) / [ ( √5 )² - ( √2 )² ]
m = ( √5 + √2 ) / [ 5 - 2 ]
m = ( √5 + √2 ) / 3
I hope this helps you.
:)
m√5 = m√2 + 1
m√5 - m√2 = 1
m ( √5 - √2 ) = 1
m = 1 / ( √5 - √2 )
m = ( √5 + √2 ) / ( √5 - √2 )( √5 + √2 )
m = ( √5 + √2 ) / [ ( √5 )² - ( √2 )² ]
m = ( √5 + √2 ) / [ 5 - 2 ]
m = ( √5 + √2 ) / 3
I hope this helps you.
:)
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