m=5,n=12 if m 1/n find k and m=6,n=?
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m12 30 6 15 n 10 4 20 8 Given proportion is m∝n1
∴m=kn1 (where k is a constant of variation)
∴k=mn ...(1)
Substituting m=12 and n=10 in equation (1), we get
k=12×10=120
(a) When n=4, k=120, m=?
⇒m=nk=4120=30
(b) When m=6, k=120, n=?
⇒n=mk=6120=20
(c) When n=8, k=120, m=?
⇒m=nk=8120=15
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