Question

m = 50 kg
m, 60 kg
V = 5 mer
Isolated system of
wo skaters
Final velocity v ?
Both the skaters
join hands​

Answer 1

Answer:

Answer

Here no any external force is applied taking two stakers A and B as a system.

then center of mass of both stakers will not change therefore they meat at center of mass, taking axis as shown in figure 1.

X

com

=

50+70

50×0+70×6

=

120

70×6

=3.5m from 50kg sketers.

X

com

= X-coordinate of center of mass.

So A mover 3.5cm

B mover (6 - 3.5) = 2.5m

Option C-correct