Question

M
9. Three boys Manish. Amit and Rahman are playing a game by standing on a circle of radius
5 m drawn in a park. Manish throws a ball to Amit, Amit to Rahman, Rahman to Manish. If the
distance between Manish and Amit and between Amit and Rahman is 6 m each, what is the
distance between Manish and Rahman?​

Answer 1

Step-by-step explanation:

Draw perpendicular OA and OB on RS and SM respectively.

Let R,S and M be the position of Reshma, Salma and Mandip respectively.

AR=AS=

2

6

=3 cm

OR=OS=OM=5 m [radii of circle]

In △OAR

OA

2

+AR

2

=OR

2

OA

2

+3

2

=5

2

OA=

25−9

OA=4 m

We know that in an isosceles triangle altitude divides the base ,

So, in △RSM

∠RCS=90

o

RC=CM

Area of △ORS=

2

1

×OA×RS

2

1

×RC×OS=

2

1

×4×6

RC×5=24

RC=4.8 m

RM=2RC=2×4.8=9.6 m

So, distance between Reshma and Mandip is 9.6 m

Answer 2

the answer is 9.6m.

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