Math, asked by murugankhanishi, 1 year ago

m^(a+b)(a-b). m^(b+c)(b-c). m^(c+a)(c-a)

Answers

Answered by kareena983
0

Answer:

The answer will be 1.

Step-by-step explanation:

For explanation kindly go to the attached and plz do mark as brainliest if it helps..

Attachments:
Answered by Anonymous
2

Answer:

1

Step-by-step explanation:

powers will be added as the base are same

(a+b)(a-b) + (b+c)(b-c) + (c+a)(c-a)

= a^2 - b^2 + b^2 - c^2 + c^2 - a^2

= 0

m^0 = 1

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