Question

m. A body with an initial velocity of 3 m s' moves with an acceleration of 2 ms. Then the dis- tance travelled in the 4th second is (a) 10 (b) 6 (c) 7 (d) 28​

Answer 1

Answer:

a) 10

Explanation:

When t=4

s= ut+ 0.5 x at^2

s= 3 x 4+ 0.5 x 2 x 4^2

s= 12+ 16

s= 28 m

When t=3

s= ut+ 0.5 x at^2

s= 3 x 3+ 0.5 x 2 x 3^2

s= 9+ 9

s= 18 m

Thus the distance travelled in the 4th second= Total distance in 4 seconds- Total distance in 3 seconds

= 28–18

= 10 m

Answer 2

$\sf\pink{Answer}$

See the attachment for ur answer Dude ☺️