Math, asked by homeworkandstudies, 5 hours ago

m and n are 2 numbers such that m + n = 15 and mn = 14 , m-n = > 0
find m^2 - n^2


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Answers

Answered by zzzsona
3

Answer:

( m - n )^2

= ( m + n )^2 - 4mn

= 15^2 - 4×14

= 225 - 56

= 169

m - n = √169

m - n = 13 ( m - n is not equal to -13 as it is given that m - n = > 0 )

m^2 - n^2

= ( m + n ) × ( m - n )

= 15 × 13

= 195

Hope this is the answer....

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