Question

M and N are the mid-points of sides DC and AB
respectively, of a rectangle ABCD. If
ar (rectangle ABCD) = 48 cm2, then ar triangle(EMC) is?​

Answer 1

Answer:

Parallelogram ABCD  and △BEC have same base BC and they are between same parallels BC and AD.

∴Areaof△BEC=  $\frac{1}{2}$area of parallelogram ABCD

                       =  $\frac{1}{2}$×$48cm^{2}$

                       =$24cm^{2}$

 AN=NB,DM=MC

NB=  $\frac{1}{2}$ AB,MC= $\frac{1}{2}$ DC

But AB=DC  ( opposite side of parallelogram ABCD)

∴NB=MC , also  NB∥MC

∴NBCM  is a  parallelogram

∴area∥gmNBCM=  $\frac{1}{2}$(∥gmABCD)=area△BEC

∴△BEC is equal in area with BNMC

$\huge\red{@alurringbabe}$