Question

m and n are two natural numbers,show that 2^m and 3^n not ends with 0 or 5 .​

Answer 1

Answer:

if we put m=1,2,3,4,5, ...etc. then we will found as results 2,4,8,16,32 for 2^m so there is no no. ended with 0 or 5 in

Again we will found 3,9,27,81,216 here we will also can't find out the no. ended with 0 or 5

Step-by-step explanation:

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