m∠AOC=108
∘
space, m, angle, A, O, C, equals, 108, degree
\qquad m \angle AOB = 3x + 4^\circm∠AOB=3x+4
∘
space, m, angle, A, O, B, equals, 3, x, plus, 4, degree
\qquad m \angle BOC = 8x - 28^\circm∠BOC=8x−28
∘
space, m, angle, B, O, C, equals, 8, x, minus, 28, degree
Find m\angle AOBm∠AOBm, angle, A, O, B:
Answers
Answered by
30
Answer:
∠AOB = 40°
∠BOC = 68°
Step-by-step explanation:
∠AOC = 108°
∠AOB = 3x + 4°
∠BOC = 8x - 28°
∠AOC = ∠AOB + ∠BOC
=> 108 = 3x + 4 + 8x - 28
=> 132 = 11x
=> x = 12
∠AOB = 3* 12 + 4 = 40°
∠BOC = 8*12 - 28° = 68°
∠AOB = 40°
∠BOC = 68°
Answered by
4
Answer:
AOC is equal to 40
Step-by-step explanation:
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