m.c.q . a small bob of mass m is tied to a straing and revolved in a veriticle circular of radius if. its speed at the higst point is r√ 3 rg the lowes point is.........
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Let the velocity at lowest point be v. then according to law of conservation of energy.
energy at lowest point= energy at highest point
⇒21mv2=mg(2r)+21m(3rg)2⇒v=7rg
At lowest point,
rmv2=T−mg⇒T=mg+rmv2=mg+rm(7rg)2
⇒T=mg+7mg=8mg
hope it helps you
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