Math, asked by gurpreet64588, 4 days ago

(M.C.Q.). The quadratic polynomial having zeroes 3 and -2 is :
a)x²-x+6 b) x²-x-6 c) x² + x + 6

Answers

Answered by 19ariz68
1

Answer:

b) X² - x -6

Step-by-step explanation:

a) x² - x + 6

By completing square method:-

x² - x X 1 +6

x² - 2 X x X 1/2 +(1/2)² - (1/2)² + 6

(x - 1/2)² = 1/4-6

(x -1/2)² = 1/4 -6x4/1x4

(x-1/2)² = 1/4 - 24/4

(x-1/2)² = -23/4

x-1/2 = +-√-23/4

x - 1/2 =+- √-23/2

x = 1/2+- √-23/2

x = 1+-√-23/2

x= 1 + √-23/2 or x = 1 - √-23/2

which is not a solution.

b) x² - x - 6

By splitting middle term

x² - 3x + 2x -6

x(x-3) + 2 (x-3)

(x+2) (x-3)

x = -2 or x = 3

which is the solution

Thanks

Answered by Mysteryboy01
1

 =  {x}^{2}  - (  \alpha  +  \beta )x +  \alpha  \beta

 =  {x}^{2}  - [ 3 + ( - 2)]x + 3 \times ( - 2) \\  \\  =  {x}^{2}  - [3 - 2]x + ( - 6) \\  \\  =  {x}^{2}  - x - 6 \\  \\  {x}^{2}  - x - 6 = 0

Similar questions