Question

m e positive odd
numbers is 143. Construct the equation and
determine the numbers by applying Sridhara
Acharyya's formula.
Answer any one question :-
(i)
x=2 + V3 and x + y = 4, then find the simplest
value of xy +
ху​

Answer 1

Step-by-step explanation:

let, the 1st no be x and 2nd no be x + 2

so , x ( x + 2 ) = 143

x² + 2x - 143 = 0

comparing the equation from ax² + bx + c = 0 we get , a = 1 , b = 2 , c = - 143

Sridhara

Acharyya's formula.

$\frac{ - b \: ± \: \sqrt{ {b}^{2} - 4ac} }{2a} = \frac{ - 2 \: ± \: \: \sqrt{ { - 2}^{2} - 4.1.( - 143)} }{2.1} \\ \frac{ - 2 \: \: ± \: \sqrt{4 + 572} }{2} \\ \frac{ - 2 \: ± \: \sqrt{576} }{2} \\ \frac{ - 2 + 24}{2} = \frac{22}{2} = 11 \\ \frac{ - 2 - 24}{2} = \frac{ - 26}{2} = - 13$

therefore , 11 and -13 are the roots of given equation.