Physics, asked by jayanth2005, 9 months ago

M.I of a cylinder of length L and radius R about an axis passing through its centre and normal to its
circular face is equal to the M.I of the same cylinder about an axis passing through the centre an
normal to its length, then L is
4) 13R
1) VR
2) v/3R
3) 13R​

Answers

Answered by Anonymous
1

Answer:

A uniform cylinder has radius R and length L. If the moment of inertia of this cylinder about an axis passing through its centre and normal to its circular face is mR22 is equal to moment of inertia of the same cylinder about an axis passing through its centre and normal to its length, then. solve to get L=√3R

Explanation:

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