Question

M.
If linear momentum of particle changes with time t
as p = (3t² + 2t + 1) kgm/s, then force acting on
particle at t = 3 s will be [NCERT Pg. 95]
(1) 10 N
(2) 20 N
(3) 15 N.
(4) 11 N​

Answer 1

Answer:

ans is

(3t²+2t+1)

6t+2

6(3)+2

18+2

=20

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Answer 2

Force acting on the particle at t=3s will be 20N.

Given:

Momentum of the particle(p)= (3t²+2t+1)

To Find:

Force acting on the particle at t=3 second.

Solution:

The Force acting on particle is given by:

F=dp/dt

dp/dt= d(3t²+2t+1)/dt

dp/dt=6t+2

F= 6t+2

Force acting on the particle when t=3s = 6(3)+2= 20N.

Force acting on the particle at t=3s is 20N.

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