M. In two moles of acetaldehyde
(CH,CHO) calculate the following
a. Number of moles of carbon
b. Number of moles of hydrogen
c. Number of moles of oxygen
d. Number of molecules of acetaldehyde
(Ans.: A. 4 mol, B. 8 mol, C. 2 mol,
D. 12.044 x 1023 molecules )
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Answer:
- 12.044×1023
Explanation:
In 1 moles of CH3CHO
2 moles of C
4 moles of H
1 moles of O
In 2 moles of CH3CHO
nc=2×2=4moles
nh=4×2=8moles
no=1×2=2moles
no.of moles =2×6.022×1023
=12.044×1023
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