Question

M invests Rs 16000 and N invests Rs 21000
at the same rate of interest per annum simple interest.
If at the end of 2 years, N gets Rs 2000 more interest
than M, find the rate of interest. ​

Answer 1

ANSWER

S.A =22400 and P.A =16000, (Lets) R=R,T=4

So, 22400= 10016000×4×R+16000

⇒640R+16000=22400

⇒R=10%

C.A = 16000(1+10010)2=16000(100110)(100110)=19360

C.I = 19360−16000=3360

Answer 2

Answer:

Step-by-step explanation:

ANSWER

S.A =22400 and P.A =16000, (Lets) R=R,T=4

So, 22400=  

100

16000×4×R

​  

+16000

⇒640R+16000=22400

⇒R=10%

C.A = 16000(1+  

100

10

​  

)  

2

=16000(  

100

110

​  

)(  

100

110

​  

)=19360

C.I = 19360−16000=3360