Question

M is a bivalent metal. write down the steps to find the chemical formulae of its compounds formed with the radicals, sulphate and phosphate

Answer 1

M is bivalent metal.

So its ion will be ${M}^{2 + }$

Sulphate is a bivalent anion. it is $SO_4^{2 - }$

So the formula of the metal sulphate will be

${M}^{2 + } + {SO_4}^{2 - } = MSO_4$

as one ion of metal M and one sulphate ion will balance each other.

Phosphate is a trivalent anion. It is ${PO_4}^{3 - }$

To balance 1 ion of phosphate, we will need 1.5 ions of the metal. So 3 ions of metal can balance 2 ions of phosphate.

$3 {M}^{2 + } + 2 {PO_4}^{3 - } = M_3(PO_4)_2$

Answer 2

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M is bivalent metal.

So its ion will be ${M}^{2 + }$

Sulphate is a bivalent anion. it is $SO_4^{2 - }$

So the formula of the metal sulphate will be

${M}^{2 + } + {SO_4}^{2 - } = MSO_4$

as one ion of metal M and one sulphate ion will balance each other.

Phosphate is a trivalent anion. It is ${PO_4}^{3 - }$

To balance 1 ion of phosphate, we will need 1.5 ions of the metal. So 3 ions of metal can balance 2 ions of phosphate.

$3 {M}^{2 + } + 2 {PO_4}^{3 - } = M_3(PO_4)_2$