Question

m is a solution of the equation x^2+2x+6=0, find
the value of (m+2)(m + 3)(m+4)(m+5)​

Answer 1

Answer:

for equal roots D=b

2

−4ac=0

⇒[2(m+1)]

2

−4m(3m+1)=0

⇒m

2

+2m+1−3m

2

−m=0

⇒−2m

2

+m+1=0

⇒2m

2

−m−1=0⇒(m−1)(m+

2

1

)=0

⇒

m=1,

2

−1