Math, asked by kajalbaghele, 6 months ago

m is midpoint of side CD of parallelogram ABCD. BM intersect AC in L and AD produced in F. prove that EC = 2BL

Answers

Answered by aryanrvt

0

Answer:

In △BMC and △EMD

∠BMC=∠EMD [Vertically opposite]

MC=DM [Given]

∠BCM=∠EDM [Alternate angles]

∴△BMC≅△EMD [By ASA]

Hence, BC=DE [By CPCT] →(1)

AE=AD+DE=BC+BC=2BC →(2)

Now, △BLC∼△ELA (AA Similarly)

EL

BL

=

AE

BC

[By CPCT]

EL

BL

=

2BC

BC

EL

BL

=

2

1

EL=2BL

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