Question

m is the center of the circle and angle mbx is 50 the the value if angle amx is

Answer 1

$M \:is \: the \: center \: of \:the \:circle \:and \\\angle {MBX} = 50\degree$

$\red { \angle {AMX} = ? }$

$In \: \triangle MBX , \\MB = MX\\\blue { (Radii\:of \: same \:circle )}$

$\angle {MBX} = \angle {MXB} = 50\degree$

$\pink { ( Angles \: opposite \:to \:equal \:sides )}$

$Now, \angle {AMX} = \angle {MBX} + \angle {MXB}$

$\blue {( Exterior \:angle \:at M \:is \:equal \:to }$

$\blue{ Sum \:of \: interior \: opposite \:angles )}$

$= 50\degree + 50 \degree \\= 100\degree$

Therefore.,

$\red {\angle {AMX} }\green { = 100\degree}$

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