Question

M is the center of the circle and MBX = 500 , the value of AMX is ………

Answer 1

as we know MB and MX are the radius of the circle

and along with the side bx it forms a isosceles triangle so MXB is also 50 degree

AMX is a exterior angle to the triangle MBX

so,

ext angle=sum of opp interior angles

so, AMX = 50+50=100 degree