Physics, asked by sameer7815, 9 months ago

m is the mass of body at rest.

what is V and C in the relation:
m=m0 / √1-(v/c)²

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Answers

Answered by shalugarg68
2

Answer:

Did you know: The General Theory of Relativity and The Special Theory of Relativity are two separate theories! (That’s why they have two separate names, duh!)

E=mc^2: Everyone knows that, right? Well, they know how to say it. Most people don’t understand the concept behind it. It’s easy to understand what it means. It’s harder to really understand it (why/how it works).

E=mc^2

This shows that energy and matter have something in common. (I forgot the rest… Hey! I read a book on it like, in Grade 6, so I can’t remember anything! Other than something about a train travelling at the speed of light, firing a cannonball…???)

Less known is:

m = m0 / sqrt(1 – (v / c)^2)

This means that as your velocity (speed) increases, and gets closer and closer to the speed of light, your mass increases (therefore, mass is related to velocity). It also proves, that it is impossible to travel faster than the speed of light. If an object were to do that, its mass would reach infinity, and that is impossible, so travelling faster than the speed of light is impossible.

m means mass

v means velocity

m0 means mass of the object when it is at rest (i.e. not moving at all [, which is impossible???])

c means the speed of light in a vacumn

For example:

Variables:

v=1/3c (v=100000km/s) (speed of object is 100000km/s)

m0=me (m0=9.109382E-031) (the object is an electron)

Constants:

c=300000km/s

me=9.109382E-31 kg (mass of an electron when it is at rest)

Solve for current (or is it called relativic, or something like that) mass (mass of object as it is travelling):

m=m0/sqrt(1-(v/c)^2)

m=9.109382E-31/sqrt(1-((1/3c)/c)^2)

m=9.109382E-31/sqrt(1-(1/3)^2)

m=9.109382E-31/sqrt(1-1/9)

m=9.109382E-31/sqrt(8/9)

m=9.109382E-31/0.94

m=9.66E-031

m>=m0

This shows that an electron traveling at 0km/s has less mass than an electron travelling at 1/3 the speed of light (100000km/s). There is a 6% increase in mass, in relation to if it were at rest.

6% is a huge difference, believe it or not. If you weigh 100 pounds now, be happy to know that you are 106 pounds now if you travel at 1/3 the speed of light. 6% can make a difference between 95 votes and 100 votes (Unfortunately, that’s not enough to win an election).

Here’s some more stuff I calculated using this equation:

If you are travelling at v, your mass will increase by p

v, p

0km/s, 0%

50000km/s, 1.4%

100000km/s, 6%

200000km/s, 34.2%

300000km/s, infinity% (sure, division by zero occurs, but according to Einstein, m0/0=infinity; makes no sense as light travels at this speed, and its mass isn’t infinity [unless light has no mass [also impossible???] and therefore 0*infinity%=0]; I’ll have to look this one up)

This graph represents the velocity of the object on the X axis, and the mass to rest mass percentage on the Y axis:

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