M IS THE MID POINT OF AB FIND TAN A/TAN M
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Step-by-step explanation:
In △ACD
tanx∘=CDAC
In △ABC
tany∘=CBAC
Now D is midpoint of CB
∴CB=2CD
Dividing (i) by (ii)
⇒tany∘tanx∘=CBACCDAC=CDCB=CD2CD=2
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