M is the midpoint of segment a b and segment cm is a median of triangle ABC complete activity
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yes m is mid point abccompletely active
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Step-by-step explanation:
GIVEN - In ∆ABC
M is midpoint such that(A-M-B)
SOLUTION- In ∆ABM and ∆BCM
A(∆ACM) AMxCM
------------- = -----------. ratio of area of∆
A(∆BCM). BMxCM
AM
= -----
BM
But M is mid point of seg AM and BM
Therefore AM=BM
A(∆ACM) : A(∆BCM) =1:1
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