Question

M is the midpoint of the side ab of a parallelogram ABCD if area of a AMCD equal to 24 cm square find area of triangle ABC​

Answer 1

Answer:

• ar(AMCD)=ar(ACD)+ar(AMC)
• ar(ACD)=ar(ABC)=1/2 ar(ABCD)
• ar(AMC)=1/2ar(ABC)=1/4 ar(ABCD)

given: ar(AMCD)=24cm²=1/2ar(ABCD)+1/4ar(ABCD)

∴ 24=1/2+1/4 ar(ABCD)

24=3/4 ar(ABCD)

32=ar(ABCD)

∴ar(ABC)=16cm²