M is the midpoint of the side DC of a parallelogram ABCD.line BM intersects seg AC at point L and line AD at point E prove that EL=2BL
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ΔBCM & ΔEDM are similar. MD=CM => BC = DE, as AD = BC, AE = 2 BC
ΔACL & ΔAEL are similar. EL / BL = AE / BC = 2
So EL = 2 BL
ΔACL & ΔAEL are similar. EL / BL = AE / BC = 2
So EL = 2 BL
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