Question

M is the molecular weight of Kmno4, the equivalent weight of kmno4 when it reacts
according to the equation 2kmno4+3H2so4+5H2c2o4gives rise to k2so4+2Mnso4+8H2o+10co2

Answer 1

Given:

M is the molecular weight of Kmno4

$\mathrm{KMnO}_{4}$  

+1≠x+4(-2)

  =0

x=8-1

 =7

Mnso4

+2

change in oxidation=7-2

   =+5

equivalent weight=molecular weight/5

                             =M/5