Question

M is the sum of the reciprocals of the consecutive integers from 201 to 300

Answer 1

a=201
d=1
an=300
an=a+(n-1)d=300
=201+(n-1)1=300
n-1=300-201
n=99+1
n=100
sn=n/2[2a+(n-1)d]
s100=100/2(2×201+99×1)
=50(402+99)
=50×501
M =25050