m' का वह मान जिसके लिए (4x2 -6x-m); (x-3) से पूर्णतया विभाजित हो,
(a) 18
(b) 45
(c) 20
(d) 36
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Answered by
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Step-by-step explanation:
Give the value of m for which (4x2 -6x-m); is exactly divisible by (x-3),
- So the given equation is 4x^2 – 6x – m
- Let f(x) = 4x^2 – 6x – m
- So to be completely divisible by x – 3 then f(3) = 0
- So putting x = 3 in the equation we get
- f(3) = 4(3)^2 – 6(3) – m
- = 4(9) – 18 – m
- = 36 – 18 – m
- = 18 – m
- Now if f(3) = 0, we get
- 18 – m = 0
- Or m = 18
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