Math, asked by vikashnishad4035, 8 months ago

m' का वह मान जिसके लिए (4x2 -6x-m); (x-3) से पूर्णतया विभाजित हो,
(a) 18
(b) 45
(c) 20
(d) 36

Answers

Answered by knjroopa
3

Step-by-step explanation:

Give the value of m for which (4x2 -6x-m); is exactly divisible by (x-3),

  • So the given equation is 4x^2 – 6x – m
  • Let f(x) = 4x^2 – 6x – m
  • So to be completely divisible by x – 3 then f(3) = 0
  • So putting x = 3 in the equation we get
  •     f(3) = 4(3)^2 – 6(3) – m
  •              = 4(9) – 18 – m
  •              = 36 – 18 – m
  •               = 18 – m
  • Now if f(3) = 0, we get
  •            18 – m = 0
  •             Or m = 18  

Reference link will be

https://brainly.in/question/42820234

Answered by studentvivek9
0

Answer:

Step-by-step explanation:

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