Question

(m) length = 2 m 25 cm and breadth = 1 m 50 cm
(iii) length = 8 m 5 dm and breadth = 6 m 8 dm
2. Pind the cost of fencing a rectangular field 62 m long and 33 m wide at * 16 per metre
3. The length and the breadth of a rectangular field are in the ratio 5:3. If its perimete
128 m, find the dimensions of the field.
4. The cost of fencing a rectangular field at 18 per metre is * 1980. If the width of the fie
23 m, find its length.
5. The length and the breadth of a rectangular field are in the ratio 7:4. The cost of fencin
field at 25 per metre is * 3300. Find the dimensions of the field.
6. Find the perimeter of a square, each of whose sides measures:
/3.8 cm
(i) 4.6 m
id) 2 m 5 dm
7. The cost of putting a fence around a square field at 35 per metre is * 4480. Find the
of each side of the field.
8. Each side of a square field measures 21 m. Adjacent to this field, there is a rectangula
having its sides in the ratio 4:3. If the perimeters of both the fields are equal, fi
dimensions of the rectangular field.
9. Find the perimeter of
(i) a triangle of sides 7.8 cm, 6.5 cm and 5.9 cm,
(i) an equilateral triangle of side 9.4 cm.
(iii) an isosceles triangle with equal sides 8.5 cm each and third side 7 cm.
10. Find the perimeter of​

Answer 1

Answer:

perimeter of rectangle = 2(l+b)

= 2(62+33) = 190 m

cost of fancing = 16×190 = ₹3040 ...

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