Question

m=log xy3 and p= log x3y2 find log (x2 ÷ y)

Answer 1

$m = log(x {y}^{3} ) \\ p = \: log( {x}^{3} {y}^{2} ) \\ \\ p - m \: = log( {x}^{3} {y}^{2} ) - \: log(x {y}^{3} ) \\ p - m \: = log( {x}^{2} \div y)$