Question

(m/m+1)+(1/m+1)+(1/m^2-1) simplify

Answer 1

Step-by-step explanation:

m^2-1^2=(m+1)(m-1)

m(m+1)+(m-1)+1÷(m+1)(m-1)

m^2-m+m-1+1÷(m+1)(m-1)

=m^2÷(m^2-1)

Answer 2

The solution is $m^{2}$/( $m^{2}$-1).

Given:

(m/m+1)+(1/m+1)+(1/m^2-1)

To find:

Simplified value

Solution:

We can simplify the given expression by taking the LCM and adding the common terms.

The given expression: (m/m+1)+(1/m+1)+(1/m^2-1)

On solving, we get

=(m/m+1)+(1/m+1)+(1/m^2-1)

=(m+1)/(m+1) + 1/$m^{2}$-1

=1+1/ $m^{2}$-1

= (( $m^{2}$-1)+1)/( $m^{2}$-1)

=( $m^{2}$-1+1)/( $m^{2}$-1)

= $m^{2}$/ ( $m^{2}$-1)

Therefore, the solution is $m^{2}$/( $m^{2}$-1).

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