m-(m-1)=3-(m-4)/3
Please solve this equation
Answers
Answer:
(6m-3(m-1)) /6 = (1*6 - 2(m-2 )) /6 6m -3m +3 = 6 -2m+4 3m +3 =10-2m 3m+ 2m = 10-3 5m = 7 m= 7/5. Hence, the value of ...
is 7/35
Answer:
Equations with linear expressions in one variable only are known as linear equations in one variable.
An algebraic equation is an equality involving variables. It has an equality sign(=). The expression on the left of the equality sign is the Left Hand Side (LHS). The expression on the right of the equality sign is the Right Hand Side (RHS).
In an equation the values of the expressions on the LHS and RHS are equal
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Solution:
m - (m-1)/2 = 1 - (m-2) / 3
first, we take the L.C.M of 2 & 3. L.C.M is 6
(6m-3(m-1)) /6 = (1*6 - 2(m-2)) /6
6m -3m +3 = 6 -2m+4
3m +3 =10-2m
3m+2m = 10-3
5m = 7
m= 7/5
Hence, the value of m= 7/5
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Step-by-step explanation:
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